First septuplet ever where all babies survived!

First septuplet ever where all babies survived!

Twin, triplets, quintuplets… How about giving birth to 7 babies at a time?! Find out why this heroic mother was almost forced by doctors to kill 4 out of 7 of the babies in her womb.

First septuplet ever where all babies survived!

Her name is Bobbi McCaughey and her husband is Kenny. Back in 1997 the couple faced the need to make serious and even heartbreaking decision. The woman got 7 babies in her womb instead of 1 or 2. Till that time there was no record of septuplets surviving the birth.

First septuplet ever where all babies survived!

Back at that time doctors had major health concerns. They were afraid the mother would not be able to nurture all the 7 babies and stay healthy. They also had a hard time believing that all the 7 little ones would survive. So, they suggested parents to kill 4 of them in Bobbi’s womb to let the other 3 survive and have proper development.

Just imagine having to make such a decision! Young parents refused to murder their kids and stood by faith. And their faith bore awesome fruits. All the 7 babies were born and survived the big day!

First septuplet ever where all babies survived!

Moreover recently the septuplets have turned 18 years of age. There are 4 boys and 3 girls. Some of the kids do have health problems, but they all make an excellent and loving family. Once again McCaughey family got in the news and went viral. The photos of grow up septuplets are amazing!

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