- UN General Assembly is set to meet from September 19 in New York
- Robert Mugabe's delegation will reportedly number 70 people, including family members
- Each person will reportedly be paid $15,000 (Ghc67k) for the 10-day trip
Zimbabwean President Robert Mugabe's delegation to this year's UN General Assembly will reportedly number a whopping 70 people, including family members.
According to IOL News, the US Embassy in Harare has questioned the inclusion of non-state operatives in the delegation to the summit.
The Mugabe family members in the delegation include daughter Bona and grandson Simbanashe, son Bellarmine Chatunga, and Russell Goreraza, Grace’s eldest son from an earlier marriage.
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The Assembly is set to sit from September 19 to 23 in New York, US. However, Mugabe's trip will last 10 days.
An anonymous diplomatic source said: “Mugabe’s entourage will be away for 10 days and government gives each member of the delegation US$1 500 (Ghc6700) per day."
The source added: “At a rate of US$1 500 per day which is paid to all the members of the delegation as per diems, this means each delegate will receive at least US$15 000 (Ghc67k) for the 10-day trip."
According to reports, the Zimbabwean government spent $36 million (Ghc160m) on international trips in the first 10 months of 2016.
This put a strain on the government, which is reportedly struggling to supply basic medication such as painkillers to hospitals.
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